2021-10-06
313 reads
2021-10-06
313 reads
An announcement on Windows containers has Steve noting that Linux might be a more desired skill in the future for SQL Server professionals.
2021-07-10
199 reads
2021-02-25
515 reads
2020-10-05
435 reads
Learn how to get Windows Authentication working on an Ubuntu SQL Server on Linux instance.
2020-09-08
3,965 reads
Running SQL Server in a container may seem daunting at first, but it’s easy once you understand the handful of commands needed. In this article, Robert Cain demonstrates how to run SQL Server in a Docker container on Ubuntu.
2020-07-06
Running SQL Server in a container may seem daunting at first, but it’s easy once you understand the handful of commands needed. In this article, Robert Cain demonstrates how to run SQL Server in a Docker container on Ubuntu.
2020-06-29
Introduction Microsoft released SQL Server on Linux, starting from SQL Server 2017. SQL Server 2019 (15.x) has the same underlying database engine on all supported platforms, including Linux. Therefore, many existing features and capabilities operate the same way on Linux. Platform File System Red Hat Enterprise Linux 7.3, 7.4, 7.5, 7.6, or 8 Server XFS […]
2020-06-01
2,366 reads
In this level of the Stairway to Linux, learn how to use the TIG stack to monitor your SQL Server instance on Linux.
2020-05-27
1,991 reads
2020-04-13
391 reads
By Steve Jones
This value is something that I still hear today: our best work is done...
By gbargsley
Have you ever received the dreaded error from SQL Server that the TempDB log...
By Chris Yates
Artificial intelligence is no longer a distant concept. It is here, embedded in the...
Hi everyone I am writing an SP where there is logic inside the SP...
Comments posted to this topic are about the item Planning for tomorrow, today -...
We have a BI-application that connects to input tables on a SQL Server 2022...
I try to run this code on SQL Server 2022. All the objects exist in the database.
CREATE OR ALTER VIEW OrderShipping AS SELECT cl.CityNameID, cl.CityName, o.OrderID, o.Customer, o.OrderDate, o.CustomerID, o.cityId FROM dbo.CityList AS cl INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID GO CREATE OR ALTER FUNCTION GetShipCityForOrder ( @OrderID INT ) RETURNS VARCHAR(50) WITH SCHEMABINDING AS BEGIN DECLARE @city VARCHAR(50); SELECT @city = os.CityName FROM dbo.OrderShipping AS os WHERE os.OrderID = @OrderID; RETURN @city; END; goWhat is the result? See possible answers