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SQL Server Failover Cluster Instances

Old Reliable Still Matters If you’ve been around SQL Server for a while, you’ve heard of Failover Cluster Instances (FCIs). They’ve been part of SQL’s high availability toolbox since...

2025-09-19 (first published: )

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Blog Post

SQL Server Is Slow (part 1 of 4)

How should you respond when you get the dreaded Email/Slack/Text/DriveBy from someone yelling at you that SQL Server is slow?   Stop. Don’t Open SSMS Yet. You’ve heard it...

2025-09-17

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The Tightly Linked View

By Steve Jones - SSC Editor

Comments posted to this topic are about the item The Tightly Linked View

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Question of the Day

The Tightly Linked View

I try to run this code on SQL Server 2022. All the objects exist in the database.

CREATE OR ALTER VIEW OrderShipping
AS
SELECT cl.CityNameID,
       cl.CityName,
       o.OrderID,
       o.Customer,
       o.OrderDate,
       o.CustomerID,
       o.cityId
 FROM dbo.CityList AS cl
 INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID
GO
CREATE OR ALTER FUNCTION GetShipCityForOrder
(
    @OrderID INT
)
RETURNS VARCHAR(50)
WITH SCHEMABINDING
AS
BEGIN
    DECLARE @city VARCHAR(50);
    SELECT @city = os.CityName
    FROM dbo.OrderShipping AS os
    WHERE os.OrderID = @OrderID;
    RETURN @city;
END;
go
What is the result?

See possible answers