2026-06-19
468 reads
SQL Server on Linux
2026-05-08
1,043 reads
2025-09-22
1,433 reads
Migrate from Linux to Windows with Availability Groups
This article describes the process to create a read-scale cross-platform SQL Server Availability Group where the primary is Linux and the secondary is Windows.
2025-07-23
390 reads
SQL Server 2022 on Ubuntu 24.04 step by step
Microsoft does not yet support this edition of Ubuntu, but there are some workarounds to make it work. This should not be used for production usage and this blog is for educational/testing purposes only.
2025-06-20
How Much Linux Do You Need?
With SQL Server on Linux becoming more popular, Steve asks if you think you need to know much about that OS.
2025-02-14
125 reads
2024-07-24
365 reads
2024-02-23
318 reads
2024-01-26
344 reads
Backup SQL Server on Linux Databases using SQL Server Agent on Windows
In this tip, we're going to look at the steps to backup SQL Server on Linux databases using SQL Server Agent on a Windows server.
2024-01-01
Blogs
Claude finds two cryptographic weaknesses (but the sky isn’t falling)
By Brian Kelley
If you haven't seen the announcement, Anthropic was able to utilize Claude (Mythos Preview)...
Generate Embeddings in SQL with Aurora and Bedrock
Most embedding pipelines on AWS have the same shape: a job reads rows out...
Resolving SQL Server Transaction Log Issues Efficiently
By Arun Sirpal
Transaction log issues are one of the quietest ways a healthy database turns into...
Forums
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Symmetric Key Encryption
Comments posted to this topic are about the item Symmetric Key Encryption
The “Successful Login” Dilemma: Why Your Login Auditing Strategy Might Be Hurting Your Server
Comments posted to this topic are about the item The “Successful Login” Dilemma: Why...
Question of the Day
Symmetric Key Encryption
If I run this statement in SQL Server 2025, how is the password encrypted?
CREATE SYMMETRIC KEY MySymmetricKey WITH ALGORITHM = AES_256, KEY_SOURCE = 'My secret key source passphrase', IDENTITY_VALUE = 'My secret identity value' ENCRYPTION BY PASSWORD = 'S&perS#cretP@ssword7'; GOSee possible answers