Deepam Ghosh

I am currently working as a DBA Lead at VGL Group, Jaipur, India. I have 6+ years of experience in MSSQL Database Administration.
I am proficient in SQL Server High Availability & Disaster Recovery (HADR) solutions, including Always On Availability Groups, SQL Server Failover Cluster Instances (FCI), Log Shipping and Cross-Platform Database Migration.
I love automating repetitive DBA tasks by writing T-SQL and PowerShell scripts.

In my free time, I enjoy watching F1 or Cricket, reading books and exploring nature.

Contained Availability Groups in SQL Server 2022

SQL Server 2022 introduced a new feature called Contained Availability Groups. It allows the Database Administrators to effectively manage the Server Level objects, such as Logins, SQL Agent jobs, etc. in an HA environment. In today's article, we will learn about this new feature of SQL Server. The Challenge of Managing Server Objects in Availability […]

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2025-08-20

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SQLServerCentral Article

SQL Automate - A DBA's Time-Saving Toolkit

SQLAutomate is a lightweight PowerShell tool that simplifies SQL Server deployment by automating both installation and post-installation configuration. Whether you're setting up one instance or dozens, this guide shows how to use SQLAutomate to save time and reduce manual work.

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2025-06-06

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Question of the Day

The Read Committed Snapshot Isolation behaviour

I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:

use master;
go

alter database AdventureWorks set read_committed_snapshot on with no_wait;
go
Then, from Session 1, I execute the following code:
--Session 1
use AdventureWorks;
go

create table ##t1 (id int, f1 varchar(10));
go

insert into ##t1 values (1, 'A');
From another session, called Session 2, I open a transaction and execute the following update:
--Session 2
use AdventureWorks;
go

begin tran;
update ##t1 
set f1 = 'B'
where id = 1;
Now, going back to Session 1, what happens if I execute this statement?
--Session 1
select f1
from ##t1
where id = 1;
 

See possible answers