Availability Group (AG)

SQLServerCentral Article

Add a Second NIC for an Availability Group to Separate Network Traffic

  • Article

Introduction Sometimes we face the scenario in an enterprise environment that the database in SQL Server Always On Availability Group (AOAG) has high concurrency read and write access from application servers. If we keep using the one network interface card for both network traffic of database connections from application servers and database mirroring between AOAG […]

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2023-05-08

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Technical Article

Always On Availability Groups Troubleshooting and Monitoring Guide

  • Article

This guide helps you get started on troubleshooting some of the common issues in AlwaysOn Availability Groups and monitoring AlwaysOn Availability Groups. It is intended to provide original content as well as a landing page of useful information that is already published elsewhere.

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2024-01-09 (first published: )

SQLServerCentral Article

A Step by Step Guide to the Availability Group (AG) Listener

  • Article

Availability databases hosted on SQL Server Always On Availability Groups (AG) can be connected using a unique Virtual Network Name (VNN), called the Availability Group Listener. When an Availability Group is enabled, clients can connect to databases in both primary and secondary replicas without explicitly specifying the SQL Server instance name. You don’t even need […]

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2021-05-17

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Question of the Day

Multiple Query Trace Flags

I want to enable two trace flags, 4199 and 4137, for a single query. How should I do this:

-- A
SELECT
  a.AddressID
, a.AddressLine1
, a.AddressLine2
, a.City
, a.StateProvinceID
, a.PostalCode
, p.FirstName
, p.LastName
FROM
  Person.Address a
  INNER JOIN person.Person AS p
    ON p.rowguid = a.rowguid
WHERE
  City           = 'SEATTLE'
  AND PostalCode = 98104
OPTION (QUERYTRACEON 4199, 4137);

-- B
SELECT
  a.AddressID
, a.AddressLine1
, a.AddressLine2
, a.City
, a.StateProvinceID
, a.PostalCode
, p.FirstName
, p.LastName
FROM
  Person.Address a
  INNER JOIN person.Person AS p
    ON p.rowguid = a.rowguid
WHERE
  City           = 'SEATTLE'
  AND PostalCode = 98104
OPTION (QUERYTRACEON 4199, QUERYTRACEON 4137);

-- C
SELECT
  a.AddressID
, a.AddressLine1
, a.AddressLine2
, a.City
, a.StateProvinceID
, a.PostalCode
, p.FirstName
, p.LastName
FROM
  Person.Address a
  INNER JOIN person.Person AS p
    ON p.rowguid = a.rowguid
WHERE
  City           = 'SEATTLE'
  AND PostalCode = 98104
OPTION (QUERYTRACEON 4199), (QUERYTRACEON 4137);

See possible answers