2001-07-23
3,189 reads
2001-07-23
3,189 reads
Ever had to calculate the number of business days between two dates? This article presents a way to solve this problem in T-SQL.
2001-07-18
12,996 reads
Steve Jones's review of a great guide for tuning the Windows 2000 OS.
2001-07-18
3,530 reads
This book discusses some of the issues that exist today in software. A good read for anyone developing software.
2001-07-11
2,942 reads
2001-07-09
3,585 reads
Looking to advance your career? Trying to get started as a DBA? Some advice from a DBA with ten years working with SQL Server
2001-07-06
9,102 reads
Continuing with Steve Jones series on string manipulation, this article looks at an interesting facet of the SELECT operator.
2001-07-04
8,827 reads
Steve Jones's review of this classic and reference. A must-have for every SQL Server DBA.
2001-07-04
5,401 reads
2001-07-02
4,052 reads
Ever needed to find the first occurrance of some data. This article looks at T-SQL querying for data in natural order.
2001-06-29
12,632 reads
By Steve Jones
I had been meaning to post this, so as I finished a piece that...
By Steve Jones
fardle-din – n. a long-overdue argument that shakes up a relationship, burning wildly through...
The post Lukáš Karlovský: I got the green light from management and built Fabric...
Hi, I would like to contribute to SQLServerCentral in peer reviews. As there are...
Comments posted to this topic are about the item Getting ANY of the data
Comments posted to this topic are about the item Why Would You Do That?
I have this data in two tables:
-- Beer table BeerIDBeerNamebrewer 5Becks Interbrew 6Fat Tire New Belgium 7Mac n Jacks Mac & Jack's Brewery 8Alaskan AmberAlaskan Brewing 9Kirin Kirin Brewing -- Beercount table BeerName BottleCount Becks 5 Fat Tire 1 Mac n Jacks 2 Alaskan Amber 4 NULL 7 Corona 2 Tsing Tao 4 Kirin 12What is returned from this query?
SELECT * FROM dbo.BeerCount AS bc WHERE bc.BeerName=ANY (SELECT b2.BeerName FROM dbo.Beer AS b2);See possible answers