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SQLServerCentral Editorial

Software Updates, Outages, Processes, and Protocols

  • Editorial

This past Thursday, February 22, AT&T had a major outage on their U.S. network. For upwards of 10 hours, hundreds of thousands of customers could not make phone calls, send or receive texts, or use mobile data for apps or browsing websites. Aside from not being able to communicate as normal, it also appeared to […]

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2024-02-24

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SQLServerCentral Article

Date and Time in SQL Server 2008

  • Article

SQL Server 2008 is well on its way to being complete and released with the release of the second CTP recently. There aren't a tremendous number of changes, but one of the more interesting ones is the changes to date and time handling in this new platform. The time and date datatypes have been separated and longtime SQL Server author Vincent Rainardi brings us a short look at how there can be used.

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2007-10-24

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SQLServerCentral Article

Passing a Table to a Stored Procedure

  • Article

SQL Server 2008, code named Katmai, has some very interesting additions to the SQL Server platform to make your development tasks easier. One of these is passing a table variable as a parameter to a stored procedure and regular columnist Jacob Sebastian shows us how.

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2009-02-13 (first published: )

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Question of the Day

The Read Committed Snapshot Isolation behaviour

I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:

use master;
go

alter database AdventureWorks set read_committed_snapshot on with no_wait;
go
Then, from Session 1, I execute the following code:
--Session 1
use AdventureWorks;
go

create table ##t1 (id int, f1 varchar(10));
go

insert into ##t1 values (1, 'A');
From another session, called Session 2, I open a transaction and execute the following update:
--Session 2
use AdventureWorks;
go

begin tran;
update ##t1 
set f1 = 'B'
where id = 1;
Now, going back to Session 1, what happens if I execute this statement?
--Session 1
select f1
from ##t1
where id = 1;
 

See possible answers