2001-06-25
7,053 reads
2001-06-25
7,053 reads
Answers to the SQL quiz that Steve Jones used to give to prospective employees.
2001-06-22
11,604 reads
This article examines the hiring practices of Steve Jones and provides some ideas for how to choose between candidates.
2001-06-22
13,435 reads
The fifth part of Steve Jones's series on programming and manipulating strings in T-SQL dealing with STUFF.
2001-06-21
10,868 reads
2001-06-20
3,636 reads
2001-06-18
1,973 reads
Steve Jones provides some notes from the field after installing SP1 on a personal edition of SQL Server
2001-06-18
2,859 reads
A new security alert affecting SQL Server was released on June 12, 2001
2001-06-14
3,612 reads
2001-06-13
3,505 reads
2001-06-11
2,480 reads
By Steve Jones
I had been meaning to post this, so as I finished a piece that...
By Steve Jones
fardle-din – n. a long-overdue argument that shakes up a relationship, burning wildly through...
The post Lukáš Karlovský: I got the green light from management and built Fabric...
Hi, I would like to contribute to SQLServerCentral in peer reviews. As there are...
Comments posted to this topic are about the item Getting ANY of the data
Comments posted to this topic are about the item Why Would You Do That?
I have this data in two tables:
-- Beer table BeerIDBeerNamebrewer 5Becks Interbrew 6Fat Tire New Belgium 7Mac n Jacks Mac & Jack's Brewery 8Alaskan AmberAlaskan Brewing 9Kirin Kirin Brewing -- Beercount table BeerName BottleCount Becks 5 Fat Tire 1 Mac n Jacks 2 Alaskan Amber 4 NULL 7 Corona 2 Tsing Tao 4 Kirin 12What is returned from this query?
SELECT * FROM dbo.BeerCount AS bc WHERE bc.BeerName=ANY (SELECT b2.BeerName FROM dbo.Beer AS b2);See possible answers