SQLServerCentral Editorial

Document yourself out of a job

Some organizations have policies in place to make sure that everything in their IT infrastructure is documented. There are runbooks, procedures, wikis, diagrams, charts, code comments, and more to make sure that knowledge is available if an employee leaves or when disaster strikes. Not only does the documentation exist, but it’s also organized and easy […]

External Article

Registration is now open for Summit 2022

Now’s the time to save your seat at the world’s largest hybrid conference for data platform professionals, taking place November 15-18! Join attendees from around the globe who are gathering in-person and online for a full week of world-class training, networking, and data-platform focused events. Register today to take advantage of discounted launch pricing, available for a limited time.

Blogs

The Book of Redgate: We Value Teams

By

This value is something that I still hear today: our best work is done...

Troubleshooting TempDB Log Full Errors When SSMS Won’t Connect

By

Have you ever received the dreaded error from SQL Server that the TempDB log...

Accelerating AI with Confidence: Why Microsoft Purview is Key to Responsible Innovation

By

Artificial intelligence is no longer a distant concept. It is here, embedded in the...

Read the latest Blogs

Forums

Is there a way for SP to know who called it?

By water490

Hi everyone I am writing an SP where there is logic inside the SP...

Planning for tomorrow, today - database migrations

By John Martin

Comments posted to this topic are about the item Planning for tomorrow, today -...

Bottlenecks on SQL Server performance

By runarlan

We have a BI-application that connects to input tables on a SQL Server 2022...

Visit the forum

Question of the Day

The Tightly Linked View

I try to run this code on SQL Server 2022. All the objects exist in the database.

CREATE OR ALTER VIEW OrderShipping
AS
SELECT cl.CityNameID,
       cl.CityName,
       o.OrderID,
       o.Customer,
       o.OrderDate,
       o.CustomerID,
       o.cityId
 FROM dbo.CityList AS cl
 INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID
GO
CREATE OR ALTER FUNCTION GetShipCityForOrder
(
    @OrderID INT
)
RETURNS VARCHAR(50)
WITH SCHEMABINDING
AS
BEGIN
    DECLARE @city VARCHAR(50);
    SELECT @city = os.CityName
    FROM dbo.OrderShipping AS os
    WHERE os.OrderID = @OrderID;
    RETURN @city;
END;
go
What is the result?

See possible answers