Adding a new shared disk to Windows Server failover Cluster is not a complex process but special care must be taken when you want to use the new disk for any existing SQL Instance. In this article, we will show you all the required steps to add the disk to WSFC and then to properly assign it to an existing SQL role in the WSFC.
2024-09-16
1,324 reads
Setting up High Availability in SQL server has some prerequisites. One of these is that the database servers must be members of the same Windows Server Failover Cluster. In this article I show how to succesfully set up WSFC and activate Cluster Aware Updating
2024-06-28
6,422 reads
In this article, we will review how to configure Always On Availability Groups in Ubuntu Server using the Pacemaker cluster. The following are the high-level steps to configure Always On Availability Groups (AOAG) with an Ubuntu server. Install SQL Server on Ubuntu 16.04 Install Pacemaker agents and configure the cluster Create Always On Availability Groups Create […]
2020-08-25
3,560 reads
2018-03-12
677 reads
This article discusses failover cluster instances and AlwaysOn groups
2012-09-04
12,342 reads
By Steve Jones
I wrote a piece on the new SUBSTRING in SQL Server 2025 and got...
By Steve Jones
If you aren’t watching the Ignite keynotes today, then you might have missed the...
Short version You want to get this running as fast as possible. Do these...
I changed my email address in Edit Profile page, but it has no effect...
Comments posted to this topic are about the item The case for "Understanding our...
Comments posted to this topic are about the item Specifying the Collation
I am dealing with issues on my SQL Server 2022 instance related to collation. I have an instance collation of Latin1_General_CS_AS_KS_WS, but a database collation of Latin1_General_CI_AS. I want to force a few queries to run with a specified collation by using code like this:
DECLARE @c VARCHAR(20) = 'Latin1_General_CI_AS'
SELECT p.PersonType,
p.Title,
p.LastName,
c.CustomerID,
c.AccountNumber
FROM Person.Person AS p
INNER JOIN Sales.Customer AS c
ON c.PersonID = p.BusinessEntityID
COLLATE @c
Will this solve my problem? See possible answers