2020-10-09
413 reads
2020-10-09
413 reads
DevOps is about being effective and getting work out to customers. Today Steve notes that the lunch factor might help you reexamine your software development process.
2020-10-09
301 reads
2020-10-08
440 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-10-08
8 reads
A number of companies worked together to ensure that they could meet the challenge of the NHS. Sharing data was critical to this effort.
2020-10-08
121 reads
Another post for me that is simple and hopefully serves as an example for people trying to get blogging as #SQLNewBloggers. Recently I was looking through the forums and...
2020-10-08 (first published: 2020-09-30)
389 reads
Data is important for AI projects, but the ethics and privacy implications are complex. A new project from Microsoft aims to help users control their data and make it available for use.
2020-10-07
115 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-10-07
16 reads
I’ve had to do some work on PostgreSQL, and I wrote an article at SQLServerCentral about getting started. Once I had things working, and could connect from Azure Data...
2020-10-07
151 reads
2020-10-06
379 reads
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Setting page visibility and the active page are often overlooked last steps when publishing...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers