Steve Jones

My background is I have been working with computers since I was about 12. My first "career" job in this industry was with network administration where I became the local DBA by default. I have also spent lots of time administering Netware and NT networks, developing software, managing smaller IT groups, making lots of coffee, ordering pizza for late nights, etc., etc.

I currently am the editor of SQL Server Central and an advocate/architect at Redgate Software. I am also the President of SQL Saturday, maintain the T-SQL Tuesday monthly party, and remember our colleagues at sqlmemorial.org.

You can find out more about me on my blog (www.voiceofthedba.com) or LinkedIn (www.linkedin.com/in/way0utwest)
  • Interests: yoga, reading, biking, snowboarding, volleyball

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Blog Post

I Want PASS to Survive

I want PASS to survive. I can say that unequivocally, because this organization has been a part of my career, my job, and my life for twenty years. Many...

2020-10-09 (first published: )

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Blogs

Solving SQL Server Mysteries with a Whole Gang of Sleuths -Scooby Dooing Episode 4

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One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...

SQL Server Availability Groups

By

Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...

Modify Power BI page visibility and active status with Semantic Link Labs

By

Setting page visibility and the active page are often overlooked last steps when publishing...

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Forums

Password Guidance

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Password Guidance

Using table variables in T-SQL

By Alessandro Mortola

Comments posted to this topic are about the item Using table variables in T-SQL

Azure elastic query credential question

By cphite

I am trying to check out elastic query between two test instances we have...

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Question of the Day

Using table variables in T-SQL

What happens if you run the following code in SQL Server 2022+? 

declare @t1 table (id int);

insert into @t1 (id) values (NULL), (1), (2), (3);

select count(*)
from @t1
where @t1.id is distinct from NULL;
 

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