One of the great things about SQL Server is that the platform has grown to include a number of configuration options and switches that allow a DBA to get the most performance from their instance that is possible. One of the downsides of the platform, however, is that any sysadmin can make changes (or db_owner […]
2022-08-03
3,131 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2022-08-02
10 reads
2022-08-01
565 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2022-08-01
22 reads
When a disaster occurs and your staff is working on it, what cadence of updates should your customers expect?
2022-08-01
182 reads
2022-07-30
321 reads
2022-07-29
368 reads
Most of work in teams, which means we are accountable to reach other, but we should also treat each other as we'd want to be treated.
2022-07-29
150 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2022-07-29
14 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2022-07-28
19 reads
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Setting page visibility and the active page are often overlooked last steps when publishing...
Hello SQL Server 2022 16.0.4212.1 running on a Windows Server 2025 Std,V 24H2, SO...
i have subscription of github copilot which i can access in vs 2022 comunity...
Comments posted to this topic are about the item Password Guidance
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers