2023-06-07
330 reads
2023-06-07
330 reads
A disaster in LA affected many companies, some of which were innocent bystanders to the event. Steve talks about the need to have some plans in place.
2023-06-05
126 reads
2023-06-05
360 reads
jouska – a hypothetical conversation that you compulsively play out in your head – a crisp analysis, a devastating comeback, a cathartic heart-to-heart – which serves as a kind...
2023-06-02
925 reads
Steve notes that sometimes we message too often, but that's a human problem, not a tool issue.
2023-06-02
147 reads
2023-06-02
323 reads
I wrote recently about finding multiple backups in a file. This post looks at how to restore one of those. The one you choose. Another post for me that...
2023-06-02 (first published: 2023-05-17)
214 reads
The PASS Data Community Summit is back in Seattle this November, the 14-17, 2023. It’s in person only, and if you can come, you should register today. Launch pricing...
2023-06-01
36 reads
2023-05-31
366 reads
How do we design a monitoring system? The Amazon Prime team realized they didn't do a good job and changed their architecture.
2023-05-31
172 reads
By Steve Jones
Finding duplicates was an interview question for me years ago, and I’ve never forgotten...
By HeyMo0sh
Over time, I’ve realised that one of the hardest parts of cloud management isn’t...
By HeyMo0sh
One of the biggest challenges I’ve faced in cloud operations is maintaining clear visibility...
Comments posted to this topic are about the item Fun with JSON II
Comments posted to this topic are about the item Changing Data Types
Comments posted to this topic are about the item Answering Questions On Dropped Columns
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
t2.*
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t1
CROSS APPLY OPENJSON(t1.value) t2; See possible answers