Ginger Daniel


SQLServerCentral Article

Steps for Installing AlwaysOn Availability Groups - SQL 2019

With SQL Server 2012 Microsoft introduced the AlwaysOn Availability Group feature, and since then many changes and improvements have been made.  This article is an update to another article, and will cover the prerequisites and steps for installing AlwaysOn in your SQL Server 2019 environment. Prerequisites Before implementing your AlwaysOn Availability Group (AG), make sure […]

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2025-11-25

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SQLServerCentral Article

SQL Log File Too Big

Is your SQL database log file too big? Maybe it is. But maybe it’s not. When log files keep growing and appear to be too big some might suggest switching to Simple recovery, shrinking the log file, and switching back to Full recovery. While this will work to shrink the file and free up disk […]

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2022-02-16

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SQLServerCentral Article

Steps for Installing AlwaysOn Availability Groups - SQL 2019

With SQL Server 2012 Microsoft introduced the AlwaysOn Availability Group feature, and since then many changes and improvements have been made.  This article is an update to another article, and will cover the prerequisites and steps for installing AlwaysOn in your SQL Server 2019 environment. Prerequisites Before implementing your AlwaysOn Availability Group (AG), make sure […]

(2)

You rated this post out of 5. Change rating

2020-12-07

151,199 reads

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Question of the Day

The Read Committed Snapshot Isolation behaviour

I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:

use master;
go

alter database AdventureWorks set read_committed_snapshot on with no_wait;
go
Then, from Session 1, I execute the following code:
--Session 1
use AdventureWorks;
go

create table ##t1 (id int, f1 varchar(10));
go

insert into ##t1 values (1, 'A');
From another session, called Session 2, I open a transaction and execute the following update:
--Session 2
use AdventureWorks;
go

begin tran;
update ##t1 
set f1 = 'B'
where id = 1;
Now, going back to Session 1, what happens if I execute this statement?
--Session 1
select f1
from ##t1
where id = 1;
 

See possible answers