Breaking Down DENSE_RANK(): A Step-by-Step Guide for SQL Enthusiasts
Learn how it works and how to use the DENSE_RANK() function in your code.
2024-04-12
3,309 reads
Learn how it works and how to use the DENSE_RANK() function in your code.
2024-04-12
3,309 reads
Unlock the power of SQL's NTILE function with our latest deep-dive article. Learn to segment your data effectively into quantiles for more nuanced analysis, discover common pitfalls and their solutions, and optimize your queries for peak performance.
2024-02-03 (first published: 2024-01-03)
4,354 reads
Dive deep into the powerful SQL window functions, LAG() and LEAD(). Explore their intricacies, discover real-world examples, and avoid common pitfalls.
2023-12-11
6,431 reads
By Steve Jones
I had been meaning to post this, so as I finished a piece that...
By Steve Jones
fardle-din – n. a long-overdue argument that shakes up a relationship, burning wildly through...
The post Lukáš Karlovský: I got the green light from management and built Fabric...
Hi, I would like to contribute to SQLServerCentral in peer reviews. As there are...
Comments posted to this topic are about the item Getting ANY of the data
Comments posted to this topic are about the item Why Would You Do That?
I have this data in two tables:
-- Beer table BeerIDBeerNamebrewer 5Becks Interbrew 6Fat Tire New Belgium 7Mac n Jacks Mac & Jack's Brewery 8Alaskan AmberAlaskan Brewing 9Kirin Kirin Brewing -- Beercount table BeerName BottleCount Becks 5 Fat Tire 1 Mac n Jacks 2 Alaskan Amber 4 NULL 7 Corona 2 Tsing Tao 4 Kirin 12What is returned from this query?
SELECT * FROM dbo.BeerCount AS bc WHERE bc.BeerName=ANY (SELECT b2.BeerName FROM dbo.Beer AS b2);See possible answers