SQLServerCentral Editorial

Sources of Inspiration

I honestly enjoy writing editorials. Something pops into my tiny brain next to something else, and I'm off. However, today, as I started to write on the topic of learning, I suddenly felt like I had just written this same editorial. I go and look, sure enough, several of my recent editorials have been on […]

Stairway to SQL Server Security

Stairway to SQL Server Security Level 11: Auditing

By defining server- and database-level audits, you can record just about any kind of event that occurs in SQL Server, which can be an invaluable source of security troubleshooting and forensic information when security breaches occur. In this stairway level you’ll learn how to define the various audit specification objects, how to capture audit data, and how to explore and use the data.

External Article

AWS Lambdas with C#

In this article, I will take you through the development process of building an API on the serverless cloud with C#. This API will be built to serve pizzas, with two endpoints, one for making pizza and the other for tasting fresh pizzas. I expect some general familiarity with AWS and serverless computing. Any previous experience with building APIs in .NET will also come in handy.

Blogs

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Forums

SQL Art, Part 4: Happy 4th of July — A British DBA's Guide to Celebrating a War We Don't Talk About

By Terry Jago

Comments posted to this topic are about the item SQL Art, Part 4: Happy...

Alamat Kantor BCA KCU KUDUS Telp:0817839777

By R4nt4u

WhatsApp: 0817839777 Jl. Jend. Ahmad Yani No.91, Magersari, Panjunan, Kec. Kota Kudus, Kabupaten Kudus,...

Alamat Kantor BCA KCU SEMARANG Telp:0817839777

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WhatsApp: 0817839777 Jl. Pemuda No.90-92, Kembangsari, Kec. Semarang Tengah, Kota Semarang, Jawa Tengah 50133

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Question of the Day

BIT_COUNT I

In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:

UserID  UserPermissions
15
23
37
What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount
from dbo.UserPermission
where UserID = 3;

See possible answers