2016-12-05
12,537 reads
2016-12-05
12,537 reads
High availability solution with cross cluster support using the new Distributed Availability Groups
2016-11-14
3,183 reads
On a not-so-busy day, I received an alert saying tempdb has grown to 90 percent of the drive size and there is only 10 percent space left on the drive. The server is a SQL Server 2014 instance and hosts AlwaysOn secondary databases.
2016-11-07
22,065 reads
If you have Always On and need to stop running database backups to the stand by server, use the script.
2016-11-21 (first published: 2016-11-01)
325 reads
In this post, I’m going to talk an issue that I found when creating an availability group listener by using SQL Server Management Studio's Add Listener. This article helps you to resolve the issue.
2016-09-06
25,345 reads
Ahmad Yaseen takes a look at how to deal with an endpoint encryption compatibility error when using SQL Server's AlwaysOn Availability Group Wizard.
2016-06-08
2,497 reads
Enabling Transparent Data Encryption on Databases in Always On Scenario
2016-02-09
13,963 reads
An alternative read-only routing technique for non-Microsoft clients.
2015-12-28
2,741 reads
2015-07-20
3,449 reads
2014-11-04 (first published: 2014-10-06)
1,392 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers