2020-09-02
165 reads
2020-09-02
165 reads
2020-09-01
489 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-09-01
14 reads
Today Steve looks back at Windows, and how Windows 10 might be the last version. Perhaps this is the model we'll see with SQL Server in the future.
2020-09-01
270 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-08-31
12 reads
2020-08-31
609 reads
The challenges of state in databases can impact our development efforts.
2020-08-31
94 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-08-28
34 reads
I’ll be speaking at the PASS Summit in 2020, and I have some things to prepare for that. I get a conference admission for the event and access for...
2020-08-28
61 reads
This week Steve wonders if you're want to tackle an exciting project for a day or a week.
2020-08-28
93 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers