2024-01-16 (first published: 2024-01-12)
526 reads
2024-01-16 (first published: 2024-01-12)
526 reads
2023-11-13
413 reads
2022-07-13
546 reads
2021-01-26
592 reads
2019-12-17
598 reads
2019-12-02
620 reads
This article will show how you can read the @@OPTIONS variable and determine your settings.
2021-01-08 (first published: 2019-11-14)
8,124 reads
2018-09-20
830 reads
2018-08-13
699 reads
2018-02-19
944 reads
By Steve Jones
This value is something that I still hear today: our best work is done...
By gbargsley
Have you ever received the dreaded error from SQL Server that the TempDB log...
By Chris Yates
Artificial intelligence is no longer a distant concept. It is here, embedded in the...
Comments posted to this topic are about the item Planning for tomorrow, today -...
We have a BI-application that connects to input tables on a SQL Server 2022...
At work we've been getting better at writing what's known as GitHub Actions (workflows,...
I try to run this code on SQL Server 2022. All the objects exist in the database.
CREATE OR ALTER VIEW OrderShipping AS SELECT cl.CityNameID, cl.CityName, o.OrderID, o.Customer, o.OrderDate, o.CustomerID, o.cityId FROM dbo.CityList AS cl INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID GO CREATE OR ALTER FUNCTION GetShipCityForOrder ( @OrderID INT ) RETURNS VARCHAR(50) WITH SCHEMABINDING AS BEGIN DECLARE @city VARCHAR(50); SELECT @city = os.CityName FROM dbo.OrderShipping AS os WHERE os.OrderID = @OrderID; RETURN @city; END; goWhat is the result? See possible answers