2025-10-01
314 reads
2025-10-01
314 reads
I flew to Amsterdam last night and hopefully by the time this publishes I’ll be at my hotel, catching up on messages and prepping for another Simple Talk Podcast...
2025-09-29
15 reads
2025-09-29
173 reads
2025-09-29
689 reads
Thanks to everyone who attended my sessions today at SQL Saturday Boston 2025. I’ve got resources listed below Slides Here are the slides from my two sessions Running a...
2025-09-27
28 reads
Fear is fueled by a lack of imagination. The antidote to fear is not bravery; it looks more like imagination – from Excellent Advice for Living What a neat...
2025-09-26
20 reads
2025-09-26
378 reads
A bit of advice from Steve to ensure you do not neglect the management of your finances for the long term.
2025-09-26
108 reads
As I use containers more and more to run various things, I decided I not only wanted to set up docker compose files, I wanted to name them something...
2025-09-26 (first published: 2025-09-03)
349 reads
2025-09-24
353 reads
By HeyMo0sh
Over time, I’ve realised that one of the hardest parts of cloud management isn’t...
By HeyMo0sh
One of the biggest challenges I’ve faced in cloud operations is maintaining clear visibility...
By Steve Jones
I come to Heathrow often. Today is likely somewhere close to 60 trips to...
Comments posted to this topic are about the item Fun with JSON II
Comments posted to this topic are about the item Changing Data Types
Comments posted to this topic are about the item Answering Questions On Dropped Columns
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
t2.*
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t1
CROSS APPLY OPENJSON(t1.value) t2; See possible answers