Steve Jones

My background is I have been working with computers since I was about 12. My first "career" job in this industry was with network administration where I became the local DBA by default. I have also spent lots of time administering Netware and NT networks, developing software, managing smaller IT groups, making lots of coffee, ordering pizza for late nights, etc., etc.

I currently am the editor of SQL Server Central and an advocate/architect at Redgate Software. I am also the President of SQL Saturday, maintain the T-SQL Tuesday monthly party, and remember our colleagues at sqlmemorial.org.

You can find out more about me on my blog (www.voiceofthedba.com) or LinkedIn (www.linkedin.com/in/way0utwest)
  • Interests: yoga, reading, biking, snowboarding, volleyball

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Blog Post

The Redgate 100

The Redgate 100 is a list of 100 people that are influential in the database world in a number of categories.I made the list in a few places, which...

2022-09-30 (first published: )

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Blogs

Solving SQL Server Mysteries with a Whole Gang of Sleuths -Scooby Dooing Episode 4

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One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...

SQL Server Availability Groups

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Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...

Modify Power BI page visibility and active status with Semantic Link Labs

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Setting page visibility and the active page are often overlooked last steps when publishing...

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Forums

Password Guidance

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Password Guidance

Using table variables in T-SQL

By Alessandro Mortola

Comments posted to this topic are about the item Using table variables in T-SQL

Azure elastic query credential question

By cphite

I am trying to check out elastic query between two test instances we have...

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Question of the Day

Using table variables in T-SQL

What happens if you run the following code in SQL Server 2022+? 

declare @t1 table (id int);

insert into @t1 (id) values (NULL), (1), (2), (3);

select count(*)
from @t1
where @t1.id is distinct from NULL;
 

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