Steve Jones

My background is I have been working with computers since I was about 12. My first "career" job in this industry was with network administration where I became the local DBA by default. I have also spent lots of time administering Netware and NT networks, developing software, managing smaller IT groups, making lots of coffee, ordering pizza for late nights, etc., etc.

I currently am the editor of SQL Server Central and an advocate/architect at Redgate Software. I am also the President of SQL Saturday, maintain the T-SQL Tuesday monthly party, and remember our colleagues at sqlmemorial.org.

You can find out more about me on my blog (www.voiceofthedba.com) or LinkedIn (www.linkedin.com/in/way0utwest)
  • Interests: yoga, reading, biking, snowboarding, volleyball

All authors

All authors

Blogs

The flight recorder: Replaying what an AI agent did on my SQL Server

By

“What exactly did it do on my server?” is the first question a DBA...

Announcements from the Microsoft Fabric Community Conference — Barcelona 2026

By

Microsoft shared a broad set of Fabric, Power BI, and SQL updates at FabCon...

Au Revoir for now

By

No, I’m not quitting or retiring. Just going on vacation, but I leave tonight...

Read the latest Blogs

Forums

Let's Talk Certifications

By Grant Fritchey

Comments posted to this topic are about the item Let's Talk Certifications

The Hidden Security Risks of Role Combination in SSAS Tabular

By Pablo Echeverria

Comments posted to this topic are about the item The Hidden Security Risks of...

The Empty Aggregate

By Steve Jones - SSC Editor

Comments posted to this topic are about the item The Empty Aggregate

Visit the forum

Question of the Day

The Empty Aggregate

I have this table in a SQL Server 2025 database: 

CREATE TABLE [dbo].[CustomerOrder]
(
[OrderID] [int] NULL,
[CustomerID] [int] NULL,
[total] [money] NULL
) ON [PRIMARY]
GO
What is returned from this code? (answers are for the sum and then the count) 
SELECT SUM(total) AS sum,
       COUNT(total) AS count
FROM dbo.CustomerOrder;

See possible answers