2007-08-06
1,700 reads
2007-08-06
1,700 reads
We've dropped an acronym!
In my rounds of the blogs today, a number of people have pointed out that SQL Server...
2007-08-03
535 reads
2007-08-03
1,691 reads
2007-08-02
1,706 reads
I'm downloading now, and you need some sort of inviation to do so, but it's available and ready for you...
2007-08-01
611 reads
2007-08-01
1,668 reads
2007-07-31
1,736 reads
Steve Jones bimonthly car update looks at driving in the UK and the differences in cars between the US and elsewhere.
2007-07-30
36 reads
2007-07-30
1,073 reads
2007-07-27
1,764 reads
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
By DesertDBA
I haven’t posted in a while (well, not here at least since I’ve been...
Comments posted to this topic are about the item Refactoring SQL Code, which is...
Comments posted to this topic are about the item The Read Committed Snapshot Isolation...
Comments posted to this topic are about the item Working with JSON/JSONB Data in...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers