Put Advanced SQL Server Features To Work
SQL is the lingua franca of server-side Web data apps. Some of the advanced features of SQL joins, views, rankings, and computed columns can drastically simplify your code.
2001-06-04
1,107 reads
SQL is the lingua franca of server-side Web data apps. Some of the advanced features of SQL joins, views, rankings, and computed columns can drastically simplify your code.
2001-06-04
1,107 reads
Getting ready to install Windows 2000 SP2? Read this article first. It provides links to resources as well as potential problems.
2001-06-01
1,069 reads
An introductory article from Microsoft on the newest version of SQL Server: SQL Server CE designed for Windows CE devices. Includes some ideas for where this version fits in your architecture.
2001-05-30
1,721 reads
A good place to start before clustering. Written by Brad McGhee, the founder of sql-server-performance.com.
2001-05-29
1,816 reads
Provides audience with information on cluster analysis algorithm.
2001-05-07
1,594 reads
In this product review by Brad McGehee, he shows you how Coefficient helps you performance tune your database.
2001-05-02
1,543 reads
This article describes how to create a Visual Basic application for merge replication that will handle both conflict and non-conflict changes between the affected tables.
2001-05-01
2,075 reads
By Steve Jones
I wrote an article recently on the JSON_OBJECTAGG function, but neglected to include an...
By HeyMo0sh
After working deep in cloud operations, I’ve learned that FinOps isn’t really about dashboards...
By gbargsley
Hello, dear blog reader. Today’s post is coming to you straight from the home...
Comments posted to this topic are about the item Creating a JSON Document I
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Comments posted to this topic are about the item Designing Database Changes Before Deployment:...
I want to create a JSON document that contains data from this table:
TeamID TeamName City YearEstablished 1 Cowboys Dallas 1960 2 Eagles Philadelphia 1933If I run this code, what is returned?
SELECT json_objectagg('Team' : TeamName)
FROM dbo.NFLTeams;
See possible answers