New feature in SQL Server 2012 - Sequence
A new feature in SQL Server 2012 is Sequence. A Sequence object provides functionality similar to Identity.
2012-10-22 (first published: 2012-09-11)
2,051 reads
Scripts
Show Job Run Snapshot
Show all job history between two dates. This is much easier than trying to navigate the job history log file viewer.
2012-10-19 (first published: 2012-09-17)
1,129 reads
Index Defragmentation
Index Defragmentation is one of the most important DBA tasks. This will significantly improve query performance.
2012-10-18 (first published: 2009-11-18)
12,449 reads
Read large C2 Audit Mode trace files
Here's a set of scripts that allow you to save pertinent information from SQL Server Profiler trace files.
2012-10-18 (first published: 2012-09-20)
612 reads
Port check for SQL Server connectivity
Generates a script to check connectivity between a list of SQL Server instances on a specified port.
2012-10-17 (first published: 2012-08-09)
2,096 reads
2012-10-16 (first published: 2012-09-21)
2,552 reads
Restore database with all necessary files
It creates the script for restoring your database with all the backups (full, differential and transaction log) needed.
2012-10-16 (first published: 2007-12-27)
5,016 reads
2012-10-12 (first published: 2012-09-10)
1,798 reads
Job Summary
This script lists the name, running and success status, last executed/currently executing step name, Average and Last duration, next run time and other related information about Jobs.
2012-10-10 (first published: 2011-11-02)
2,113 reads
Tables, Queues, and Indices as a Percent of DB Size
Two views that give you a variety of stats, sortable as a percent of DB size, for tables, indiceses, XML indices, and Service Broker Queues.
2012-10-09 (first published: 2008-06-16)
3,076 reads
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Question of the Day
BIT_COUNT I
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers