2012-04-26 (first published: 2012-04-02)
1,065 reads
2012-04-26 (first published: 2012-04-02)
1,065 reads
2012-04-25 (first published: 2012-04-02)
2,289 reads
2012-04-24 (first published: 2012-03-30)
1,875 reads
This script will list the operators that have jobs
that are configured to notify them with alerts.
2012-04-23 (first published: 2012-03-29)
1,021 reads
The scripts provided below will show you the "Recovery Mode (Model)" for any given database
2012-04-19 (first published: 2008-03-18)
2,027 reads
Procedure to find any object such as table/stored procedure by its name, or find for ant text inside stored procedures, functions.
2012-04-18 (first published: 2008-05-28)
3,022 reads
2012-04-17 (first published: 2008-02-15)
7,505 reads
A script to check the owners, collations and backups on the server.
2012-04-16 (first published: 2007-10-19)
2,656 reads
2012-04-13 (first published: 2007-10-19)
3,420 reads
Restore server/database users and roles from another server when we are restoring databases to another server.
2012-04-12 (first published: 2007-10-23)
3,136 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
WhatsApp CS 628218520153 ITC ROXY MAS, Jl. Kh Hasyim Ashari No.125 Basement 13, RW.8,...
WhatsApp CS 628218520153 Jl. Sukarjo Wiryopranoto No.28 C, RT.1/RW.1, Kb. Klp., Kecamatan Gambir, Kota...
WhatsApp CS 628218520153 Jl. KH Fachrudin 36 Blok D/23, Kp. Bali, Kecamatan Tanah Abang,...
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers