System Development Life Cycle

Technical Article

Software Tool Design: Design by Sketching

  • Article

Developers can get so used to relying on computers for everything that they can forget how useful it can be in the design process to elicit and refine ideas whilst working in groups, using a sketchbook, pencils and crayons. Sometimes we all need a jolt to force us to take a different approach to solving software design problems.

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2008-08-29

3,357 reads

External Article

Deploying Database Developments

  • Article

When a team is developing a database application, it is a mistake to believe that deployment is a simple task. It isn’t. It has to be planned, and scripted. Alexander Karmanov describes many of the problems you’re likely to meet, and provides an example solution that aims to save the DBA from the nightmare complexity of an unplanned deployment.

2008-07-01

3,321 reads

External Article

Testing SQL Stored Procedures Using LINQ

  • Article

The need to test a program that accesses and manipulates a back-end SQL Server® database is very common. In many such cases, the application interacts with the back-end data through the use of SQL stored procedures. In this type of scenario, you can think of the stored procedures as auxiliary methods of the system under test; and they must therefore be tested just like any other module in the system.

2008-05-08

4,526 reads

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Question of the Day

Multiple Query Trace Flags

I want to enable two trace flags, 4199 and 4137, for a single query. How should I do this:

-- A
SELECT
  a.AddressID
, a.AddressLine1
, a.AddressLine2
, a.City
, a.StateProvinceID
, a.PostalCode
, p.FirstName
, p.LastName
FROM
  Person.Address a
  INNER JOIN person.Person AS p
    ON p.rowguid = a.rowguid
WHERE
  City           = 'SEATTLE'
  AND PostalCode = 98104
OPTION (QUERYTRACEON 4199, 4137);

-- B
SELECT
  a.AddressID
, a.AddressLine1
, a.AddressLine2
, a.City
, a.StateProvinceID
, a.PostalCode
, p.FirstName
, p.LastName
FROM
  Person.Address a
  INNER JOIN person.Person AS p
    ON p.rowguid = a.rowguid
WHERE
  City           = 'SEATTLE'
  AND PostalCode = 98104
OPTION (QUERYTRACEON 4199, QUERYTRACEON 4137);

-- C
SELECT
  a.AddressID
, a.AddressLine1
, a.AddressLine2
, a.City
, a.StateProvinceID
, a.PostalCode
, p.FirstName
, p.LastName
FROM
  Person.Address a
  INNER JOIN person.Person AS p
    ON p.rowguid = a.rowguid
WHERE
  City           = 'SEATTLE'
  AND PostalCode = 98104
OPTION (QUERYTRACEON 4199), (QUERYTRACEON 4137);

See possible answers