MDX (MultiDimensional Expressions) in 148 minutes
If you want to understand the fundamentals of MDX in less than 3 hours - this article can be helpful.
2019-05-07
11,101 reads
If you want to understand the fundamentals of MDX in less than 3 hours - this article can be helpful.
2019-05-07
11,101 reads
SQL Server Analysis Services (SSAS) is an analytical data engine used in decision support and business analytics. It provides enterprise-grade semantic data models for business reports and client applications, such as Power BI, Excel, Reporting Services reports, and other data visualization tools. When paired with ADO.NET data providers, you can create cubes from external data […]
2019-04-30
3,677 reads
The final day of Simon's journey to improve his OLAP knowledge and build a prototype cube.
2012-11-16
1,066 reads
2012-11-15
909 reads
Day 5, the first real day of the Summit. Amir Netz' session and a little cube work.
2012-11-14
1,069 reads
Day 4 is the halfway point. Another pre-con, this one from Peter Myers that looks at Power View and Matrix reports.
2012-11-13
1,218 reads
2012-11-12
1,689 reads
2012-11-09
1,697 reads
2012-11-08
3,286 reads
2012-11-07
966 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers