The “Successful Login” Dilemma: Why Your Login Auditing Strategy Might Be Hurting Your Server
From bloated error logs to risky logon triggers, a guide to auditing connections without killing performance.
2026-07-29
2,331 reads
From bloated error logs to risky logon triggers, a guide to auditing connections without killing performance.
2026-07-29
2,331 reads
Build a process that captures your SQL Agent job history and changes across time.
2026-07-24
1,623 reads
2026-07-24
533 reads
Tracking metrics and reporting on them to others can help ensure everyone is aware of how your database servers are functioning. However, Steve notes that we have to agree on what we are measuring.
2026-07-22
209 reads
2026-07-15
730 reads
2026-07-08
434 reads
2026-06-30 (first published: 2026-06-29)
1,389 reads
I used the guide in a previous tip on Install SQL Server 2008 on a Windows Server 2008 Cluster Part 1 to install a SQL Server 2008 on a Windows Server 2008 failover cluster (WSFC). Now, I would like to upgrade and migrate my SQL Server 2008 failover clusters to SQL Server 2022 running on Windows Server 2022. What is the process for installation and configuration?
2026-06-26
2026-05-29
621 reads
2026-05-15
869 reads
By ReviewMyDB
My T-SQL Tuesday #202 entry for Marlon Ribunal's invitation on memorable SQL Server outages....
A RAG pipeline that answers questions in the demo is not the same thing...
By Steve Jones
“A multitude of bad ideas is necessary for one good idea” – from Excellent...
Hello everyone, Last week we performed an upgrade of our SQL Server instance, moving...
Comments posted to this topic are about the item Adding new column with DEFAULT
I've got a web application for my side business. I've added a SQL Server...
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers