2015-06-18
1,647 reads
2015-06-18
1,647 reads
With no end to company hack attacks in sight, will we get new regulation instead?
2015-06-16 (first published: 2011-06-22)
215 reads
I’m leaving today for a trip to Cambridge, UK. I do this 2-3 times a year, but this one is...
2015-06-16
630 reads
The debate over how to change code or solve a problem can create arguments that last for years. Steve Jones notes the idea of limiting debates to five minutes is interesting.
2015-06-15
183 reads
I’m writing this post as a way to help motivate the #SQLNewBloggers out there. Read the bottom for a few...
2015-06-15
2,602 reads
CSS Engineers at Microsoft are reporting more space issues with database systems. Steve Jones has a few comments.
2015-06-15
140 reads
2015-06-12
135 reads
In this article on tSQLt, learn how you can use the AssertResultSetsHaveSameMetaData method from the framework to enforce your API.
2015-06-11
5,489 reads
I’m writing this post as a way to help motivate the #SQLNewBloggers out there. Read the bottom for a few...
2015-06-11 (first published: 2015-06-03)
3,310 reads
Steve Jones is searching for anyone that is using In-Memory OLTP tables in production.
2015-06-11
170 reads
By Steve Jones
It’s time for T-SQL Tuesday again and this is a great prompt to start...
By alevyinroc
T-SQL Tuesday is a monthly blog party hosted by a different community member each...
How I used AI for this postChatGPT to generate images based on info specifically...
Bonjour à tous, La semaine dernière, nous avons effectué une mise à niveau de...
Comments posted to this topic are about the item Adding new column with DEFAULT
I've got a web application for my side business. I've added a SQL Server...
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers