2019-08-13
2,761 reads
2019-08-13
2,761 reads
2019-08-13
1,173 reads
Learning to become a DBA is often a winding and twisty road. Steve has a little advice today.
2019-08-13
252 reads
2019-08-12
679 reads
2019-08-12
276 reads
2019-08-09
853 reads
Hiring at Basecamp is interesting. I caught this interview and think it’s a good look at a process most of us have gone through, but perhaps not thought about....
2019-08-09
29 reads
Steve wants to know what's in your current home lab. Leave a note and help others learn to set one up.
2019-08-09
610 reads
2019-08-08
662 reads
I’ve been slowly working my way through the 50 days of Kubernetes (K8s). As you might have guessed if you remember my first post, this has been more than...
2019-08-08 (first published: 2019-07-15)
424 reads
By HeyMo0sh
Over time, I’ve realised that one of the hardest parts of cloud management isn’t...
By HeyMo0sh
One of the biggest challenges I’ve faced in cloud operations is maintaining clear visibility...
By Steve Jones
I come to Heathrow often. Today is likely somewhere close to 60 trips to...
Comments posted to this topic are about the item Fun with JSON II
Comments posted to this topic are about the item Changing Data Types
Comments posted to this topic are about the item Answering Questions On Dropped Columns
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
t2.*
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t1
CROSS APPLY OPENJSON(t1.value) t2; See possible answers