2023-03-27 (first published: 2023-03-24)
464 reads
2023-03-27 (first published: 2023-03-24)
464 reads
2023-03-27
347 reads
2023-03-27
463 reads
Today’s coping tip is to discover the joy in the simple things in life. This is the last coping tip for now. It’s been 3 years, and I hope...
2023-03-24
25 reads
I have been experimenting a bit with graph databases, trying to learn more about them. One of the platforms I wanted to experiment with was RedisGraph. This post looks...
2023-03-24 (first published: 2023-03-23)
69 reads
Zero downtime used to be more important in Steve's job, but lately it seems customers aren't as concerned.
2023-03-24
135 reads
I delivered my talk on Architecting Zero Downtime Deployments yesterday at VS Live Las Vegas 2023. It went fairly well, even though I ran some incorrect code somewhere. Apologies...
2023-03-24 (first published: 2023-03-23)
60 reads
Today’s coping tip is to focus your attention on the good things you take for granted. My life is great. I used to say perfect, but a few struggles...
2023-03-23
16 reads
Thanks to everyone who attended my talk at VS Live Las Vegas 2023 on graph databases. I hope you enjoyed it, and if you have questions, please feel free...
2023-03-23
20 reads
2023-03-22
424 reads
By Steve Jones
This is timely, as I’m currently on a boat in the Adriatic taking a...
You can find the slides and SQL scripts for my session “Spice up your...
By SQLPals
How to Clear the SSMS Cache (SSMS 21 and Later) Updated...
Comments posted to this topic are about the item Risk Vs Reward, The never...
Telp/Wa 628218200203 Jl. Cideng Timur No.11 F, RT.5/RW.4, Petojo Utara, Kecamatan Gambir, Kota Jakarta...
Telp/Wa 628218200233 Kem Tower, Jl. Landas Pacu Barat No.Kav 2 Blok B, RW.10, Gn....
We have this code that sets some status values and then queries them using the CHOOSE() function in SQL Server 2025.
CREATE TABLE Status
(
StatusID INT,
StatusDescription VARCHAR(20)
);
GO
INSERT dbo.Status
(
StatusID,
StatusDescription
)
VALUES
(0, 'Uncategorized'),
(1, 'Active'),
(2, 'Inactive'),
(3, 'Temp');
GO
SELECT CHOOSE(StatusID, 'Unknown', 'Active', 'Inactive', 'Temporary')
FROM Status;
When the SELECT runs, what is returned? See possible answers