Paid Flyway Advantages–Undo and Check
The Community edition of Flyway has some nice basic features, and it works well for many people. However, it requires you to do a lot of the heavy lifting...
2022-10-31
148 reads
The Community edition of Flyway has some nice basic features, and it works well for many people. However, it requires you to do a lot of the heavy lifting...
2022-10-31
148 reads
2022-10-31
738 reads
This is another memory of the PASS Summit, this one inspired by Argenis Fernandez, who wanted to raise money for Doctors Without Borders. I wrote a bit about the...
2022-10-28
6 reads
Today’s coping tip is to realize you can’t do everything; what are your three top priorities now? It’s a few weeks before the Data Community Summit, volleyball starts, vacation...
2022-10-28
2 reads
A few years ago at the Summit, Andy Warren and I set up a Game night. We convinced the organizers to give us a room for a few hours...
2022-10-28
5 reads
2022-10-28
351 reads
2022-10-28
155 reads
Today’s coping tip is to write down three specific things that have gone well recently. Easy, as a lot of things have gone well. I’m going with some travel...
2022-10-27
4 reads
Our design and modeling is often done with some level of uncertainty. Steve has a few guidelines today.
2022-10-26
174 reads
Today’s coping tip is to recognize that you have a choice in what to prioritize A good one for me, especially as I’m a little stressed and overloaded with...
2022-10-26
9 reads
Setting page visibility and the active page are often overlooked last steps when publishing...
By Steve Jones
It’s time for T-SQL Tuesday again and this time Todd Kleinhans has a great...
By Steve Jones
Recently I was working in VS Code and I saw a walkthrough for the...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers