2023-03-17
4,929 reads
Shivayan Mukherjee
- Interests: coding, travelling, outdoor games
2023-02-17 (first published: 2023-02-10)
11,543 reads
Cassandra Springboot Integration
In this article, you will see how to initialize a Cassandra database that is used in a Springboot application.
2022-11-04
2,519 reads
2022-10-14
8,360 reads
PostgreSQL Triggers Part 2
Article Overview In this article, we will learn how to drop, alter, enable, and disable a PostgreSQL trigger. In the 1st part of this series, we got an overall view of database triggers, PostgreSQL-specific triggers, types of PostgreSQL triggers, and how to create a trigger with basic syntax and examples. If you haven't read it […]
2022-09-23
1,617 reads
2022-08-24
2,285 reads
PostgreSQL Springboot Integration Using JDBC Template
Learn how you can use Springboot to automatically make data changes for a new database in an application.
2022-06-03
7,847 reads
PostgreSQL Date And Time Part 2
In the second part of this PostgreSQL date time series, we examine a number of commonly used functions for getting current dates and times and converting strings to dates and times.
2021-09-22
3,552 reads
PostgreSQL Date And Time Part 1
This article shows the basics of using the age, and current date/time functions in PostgreSQL.
2021-08-09
2,467 reads
PostgreSQL Hibernate Integration
Overview PostgreSQL is a free and general purpose open source object-relational database system that uses and extends the SQL language while Hibernate is probably the most popular ORM tool. If you are not familiar with PostgreSQL then I suggest you to go through this link below before going ahead in this article. This article is […]
2021-07-16
26,422 reads
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SQL Art, Part 4: Happy 4th of July — A British DBA's Guide to Celebrating a War We Don't Talk About
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Question of the Day
BIT_COUNT I
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers