An Age of AI?
The age of artificial intelligence seems to be here, but it's a little different to what we were promised.
2019-07-22 (first published: 2016-02-15)
434 reads
The age of artificial intelligence seems to be here, but it's a little different to what we were promised.
2019-07-22 (first published: 2016-02-15)
434 reads
2016-10-17
93 reads
2016-04-18
76 reads
As yet more personal details are spilled by preventable security lapses, what's
2015-11-02
274 reads
The observation that people hear what they want to hear is not a new one, and yet the extent to which people will go out of their way to ignore or misinterpret evidence can still surprise.
2015-06-01
107 reads
Here are some fine, affordable products to completely destroy your work-life balance.
2015-04-27
161 reads
2015-02-16
77 reads
As working hours in tech trend upwards, we look at some ways to make life easier.
2014-10-13
124 reads
An ingenuous use of existing data leads to the thought - when are we so deep in our work that we can't see how to improve?
2014-08-18
39 reads
Trying to take the time to fix sub-par processes has some surprising parallels in nature.
2014-04-28
172 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers