2015-12-30
1,360 reads
2015-12-30
1,360 reads
Most people blog to share something they've done, and hopefully with the idea that someone else will learn and benefit from it. Steve Jones is happy to share code, but not everyone seems to be in agreement. In any case, you ought to respect the author's wishes.
2015-12-29 (first published: 2011-01-25)
327 reads
2015-12-29
1,113 reads
In the final Database Weekly of 2015, Steve Jones looks at a CIO's column on workplace change.
2015-12-28
122 reads
SQL Injection isn't special code. It consists of regular, valid T-SQL that is unexpected by the application. Steve Jones notes that using the principle of least privilege can help to limit the damage from SQL Injection if the application fails to properly check input.
2015-12-28 (first published: 2011-04-12)
605 reads
2015-12-28
1,143 reads
This Friday Steve Jones has a poll about which SQL Servers might impress you. Is there a company or installation that you think would really showcase the power and scalability of SQL Server?
2015-12-25 (first published: 2011-05-06)
497 reads
2015-12-25 (first published: 2015-12-17)
1,709 reads
A secret project is underway up in Redmond, according to sources not so high up in the development team. A port is partially working for various reasons. Read this exclusive scoop!
2015-12-25 (first published: 2005-04-01)
48,147 reads
2015-12-25
1,712 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
Many years ago, before I joined Oracle, I was working on a major modernisation...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
WhatsApp: 0817839777 Jl. Jend. Ahmad Yani No.91, Magersari, Panjunan, Kec. Kota Kudus, Kabupaten Kudus,...
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers