TSQL Challenge 36 - Create a graph/Chart with TSQL
This challenge invites you to create a graph/chart using T-SQL
2010-08-09
3,806 reads
This challenge invites you to create a graph/chart using T-SQL
2010-08-09
3,806 reads
Red Gate Software is having another million dollar challenge. If you work for a small software company, or have a software product of your own, read about the challenge.
2010-08-06
4,013 reads
Take a moment and vote on the new SQL Rally logo that will be used for the event next spring.
2010-08-06
1,762 reads
A webinar from the PASS Performance VC on Aug 3, 2010
2010-08-02
3,194 reads
This challenge has a (fake) reference to the 24 Hours of PASS event and your task is to count the number of attendees who watched the complete presentation of each speaker.
2010-07-26
1,475 reads
There are some good reasons to think about attending the 2010 PASS Community Summit.
2010-07-23 (first published: 2010-02-25)
3,779 reads
This challenge is all about searching for two keywords in a string with a maximum distance of 'one word' between them.
2010-07-12
1,700 reads
The July 2010 PASS Performance VC Presentation by Jason Strate on July 6th 12:00 PM EDT (GMT -4).
2010-07-06 (first published: 2010-07-01)
3,239 reads
This fall you have the chance to learn from a number of SQL Server experts and get a little vacation at the same time on a SQL Cruise.
2010-06-30
1,750 reads
This problem is related to a reservation system where customers book a service and pay it in one or more transactions which may happen on different dates.
2010-06-28
1,601 reads
Programmatic Tool Calling with the Claude SDK Every morning somebody on the team runs the...
By Steve Jones
mauerbauertraurigkeit – n. inexplicable urge to push people away, even close friends whose company...
By Brian Kelley
Pinal Dave wrote up his methodology for what to do when you discover bad...
Comments posted to this topic are about the item Why SQL Server Database Attach...
Comments posted to this topic are about the item Fixing P1 Queries
In SQL Server 2025, I run this code:
select bit_count('A')
What is returned? See possible answers