Articles

SQLServerCentral Article

An Identity Crisis

SQL Server includes autonumber of identity columns despite the fact that they are not SQL-92 compliant. There is quite a bit of debate over the use of them in your database, but if you do decide to use them, you should be aware of potential problems. New author Troy Ketsdever brings us a story about his identity crisis and how it was solved.

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2005-03-23

10,239 reads

External Article

SQL Server 2005 Security - Part 4

In this article, we will conclude our coverage of security related changes in SQL Server 2005 Beta 2 (although we will continue discussion of improvements in other functionality areas throughout the reminder of this series). The topics we will focus on here are code and module signing, modifications of SQL Server Agent and SQL Profiler operations, as well as monitoring and auditing changes.

2005-03-23

2,123 reads

SQLServerCentral Article

Migration to Production

SQL Server is an easy to use product in many ways, much better than the other major RDBMSs out there. However it's source control and ease of moving changes from development to production needs some work. Having a solid process is as important as good tools and new author Grant Fritchey brings us his proven method for moving changes through QA into production.

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2005-03-22

9,472 reads

Technical Article

Creating a User Defined Aggregate with SQL Server 2005

SQL Server doesn't have a Product aggregate function. A recent blog post by Karen Watterson pointed out that Microsoft Knowledge Base article Q89656: Simulating a PRODUCT() Aggregate Function discusses how to achieve the Product aggregate functionality using the POWER function. We e-mailed about it and she challenged me to create a Product aggregate in SQL Server 2005. I decided to accept the challenge.

2005-03-22

1,489 reads

External Article

SQL Server 2000 Security - Part 6 - Ownership and Object Permissions

We have described, so far, authorization based on a predefined fixed server (determining a set of SQL server-wide privileges) and database (applying to database objects and activities) roles. We have also discussed application roles, which makes the level of permissions independent of those assigned to a SQL Server login or a database user account. Now it is time to look into permissions from the point of view of database objects. There are two main factors that play a role in determining how access rights to them are evaluated - their ownership and custom permissions. We will discuss the first one of these topics in this article and will continue with the other one in the next installment of this series.

2005-03-22

2,349 reads

SQLServerCentral Article

Securing SQL Backups

SQL Server does many things very well, but securing itself is not one of them. While securing your server requires some effort, there is an area that many people forget. Securing your backups! Brian Kelley, our resident security expert, brings some advice and ideas for ensuring your data will not be stolen.

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2005-03-21

9,013 reads

Technical Article

Exploring 'ON DELETE SET NULL' in SQL Server 2005

At first glance, the 'ON DELETE SET NULL' option in SQL Server 2005 may not seem like a big deal, but once you've seen how it can be used, I think you will be impressed. The basics? If Order.CustomerID has a foreign key to Customer.CustomerID and a customer is deleted, 'ON DELETE SET NULL' causes the CustomerID field in each of that customer's orders to be set to NULL. It allows the "parent" record to be deleted and sets the "child" record's column to NULL. A normal foreign key says Order.CustomerID must match a record in Customer. An 'ON DELETE SET NULL' foreign key says that if Order.CustomerID is not null, then its value must match a record in Customer.

2005-03-18

1,579 reads

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The Tightly Linked View

By Steve Jones - SSC Editor

Comments posted to this topic are about the item The Tightly Linked View

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Question of the Day

The Tightly Linked View

I try to run this code on SQL Server 2022. All the objects exist in the database.

CREATE OR ALTER VIEW OrderShipping
AS
SELECT cl.CityNameID,
       cl.CityName,
       o.OrderID,
       o.Customer,
       o.OrderDate,
       o.CustomerID,
       o.cityId
 FROM dbo.CityList AS cl
 INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID
GO
CREATE OR ALTER FUNCTION GetShipCityForOrder
(
    @OrderID INT
)
RETURNS VARCHAR(50)
WITH SCHEMABINDING
AS
BEGIN
    DECLARE @city VARCHAR(50);
    SELECT @city = os.CityName
    FROM dbo.OrderShipping AS os
    WHERE os.OrderID = @OrderID;
    RETURN @city;
END;
go
What is the result?

See possible answers