2013-04-03 (first published: 2013-03-08)
1,692 reads
Scripts
2013-04-02 (first published: 2008-09-11)
15,391 reads
2013-04-01 (first published: 2013-03-08)
1,809 reads
2013-03-29 (first published: 2013-03-08)
1,439 reads
Backup history details EMAIL (past 24 hours) in HTML format
Get backup status email daily to your inbox in HTML format.
2013-03-27 (first published: 2013-03-14)
2,401 reads
2013-03-26 (first published: 2013-03-15)
792 reads
Monitor current transactions and get all required information
Check which transactions are running, query text, percent complete , query_plan, wait_type, and how long they have been running etc. - with one command.
2013-03-25 (first published: 2013-03-15)
2,314 reads
Powershell - Document your environment
This script is an improvement from my original script entitled "Powershell - Query SQL Servers Operating system details".
2013-03-22 (first published: 2013-02-27)
2,408 reads
2013-03-21 (first published: 2013-02-27)
1,267 reads
2013-03-19 (first published: 2013-03-01)
1,061 reads
Blogs
KDA: Echoes of Deception - Case 6
By Zikato
A cryptic message, a book cipher hidden in art provenance records, and a trail...
Capturing My Own Metrics: #SQLNewBlogger
By Steve Jones
A customer was trying to compare two tables and capture a state as a...
Red Flags in Your Query (T-SQL Tuesday #200)
By Zikato
When I'm looking at a query, I bet it's bad if I see... a...
Forums
Alamat Kontak Bank BCA KCP Cijerah WA {08218154393}
WA:08218154393 Istana Regency Sudirman, Jl. Raya Cijerah Raya No.2 Ruko No 19 & 20,...
Alamat Kontak BCA KCU BANDUNG WA {08218154393}
WA:08218154393 Jl. Asia Afrika No.122-124, Paledang, Kec. Lengkong, Kota Bandung, Jawa Barat 40261
BIT_COUNT II
Comments posted to this topic are about the item BIT_COUNT II
Question of the Day
BIT_COUNT II
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers