2014-09-29 (first published: 2010-02-04)
9,507 reads
2014-09-29 (first published: 2010-02-04)
9,507 reads
A fast and accurate way to calculate the distance in miles between two points, based on the latitudes and longitudes.
2014-09-26 (first published: 2009-01-31)
9,249 reads
2014-09-25 (first published: 2010-12-23)
26,163 reads
2014-09-23 (first published: 2010-02-17)
11,510 reads
This script will allow you get all the users and roles with permission on objects on all databases.
2014-09-18 (first published: 2009-03-05)
35,795 reads
Populate a calendar table with user set interval start and end datetime values.
2014-09-16 (first published: 2014-02-21)
2,114 reads
Populate a calendar table with user set interval start and end datetime values.
2014-09-15 (first published: 2014-02-21)
2,015 reads
2014-09-12 (first published: 2011-12-22)
3,345 reads
Transpose N rows of a table (v2.0 allows user to specify the table's schema)
2014-09-10 (first published: 2010-01-29)
2,068 reads
Create crosstab queries as easily as MS Access with a lot more power.
2014-09-09 (first published: 2009-04-02)
4,507 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
WhatsApp CS 628218520154 Jl. Suryopranoto No.40, RT.12/RW.7, Petojo Utara, Kecamatan Gambir, Kota Jakarta Pusat,...
WhatsApp CS 628218520154 Jl. Pegangsaan Timur No.1, Cikini, Kec. Menteng, Kota Jakarta Pusat, Daerah...
WhatsApp CS 628218520154 Jl. Pintu Air Raya No.36 Q, RT.6/RW.1, Ps. Baru, Kecamatan Sawah...
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers