2017-03-21 (first published: 2017-03-15)
504 reads
2017-03-21 (first published: 2017-03-15)
504 reads
Return values from MongoDB on Linux server with Powershell
2017-03-20 (first published: 2017-03-16)
1,202 reads
This script will show you all the tables that are being published with sizes.
2017-03-16 (first published: 2017-03-13)
3,562 reads
2017-03-08 (first published: 2017-02-16)
2,069 reads
2017-03-07 (first published: 2017-03-01)
1,283 reads
This trigger will send mail notification once a row is written in the suspect pages table
2017-03-03 (first published: 2017-02-21)
533 reads
This script will list all missing indexes with create statements.
2017-03-01 (first published: 2017-02-24)
1,358 reads
2017-02-28 (first published: 2015-06-22)
2,127 reads
This script serves to display the content of the waiting resource. It is divided in two parts. In first one I'm using t-sql, and in second one I accomplished the same task using SQLCRL.
2017-02-27 (first published: 2017-02-21)
1,341 reads
The code works well for an automation process that needs to have xp_cmdhsell turned on.
2017-02-22 (first published: 2017-02-13)
1,666 reads
By Steve Jones
Here are the resources for my talk at Day of Data Boston. Slides –...
By Steve Jones
I’ve covered the values in a number of previous posts on the Book of...
By Arun Sirpal
When the evidence names the database, it says so. When it doesn’t, it stops....
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers