Get Data, Log, Backup, and Binn Directory (SQL Server 2005)
Use this to find Data, Log, Backup, and Binn Directory for SQL Server 2005
2008-12-15 (first published: 2008-11-18)
1,679 reads
Use this to find Data, Log, Backup, and Binn Directory for SQL Server 2005
2008-12-15 (first published: 2008-11-18)
1,679 reads
Change owner of a maintenance plan so the SQL Agent jobs have the correct owner for running.
2008-12-12
3,200 reads
2008-12-12 (first published: 2008-11-19)
879 reads
Generates a dataset for determining when subscriptions fail to send e-mail or post reports to file shares.
2008-12-10 (first published: 2008-11-19)
1,321 reads
2008-12-08 (first published: 2008-11-07)
485 reads
A quick way to get a snapshot of what data types are being used in all user tables.
2008-12-04 (first published: 2008-10-02)
1,137 reads
2008-12-03 (first published: 2008-10-29)
1,129 reads
This query states the execution status of the job i.e. Executing, idle etc. you also modify and search the jobs by changing the search condition.
2008-12-02
1,065 reads
2008-12-02 (first published: 2008-10-30)
1,439 reads
This provides information about traces that are defined on SQL Server 2005.
2008-12-01 (first published: 2008-10-25)
1,301 reads
By Steve Jones
Here are the resources for my talk at Day of Data Boston. Slides –...
By Steve Jones
I’ve covered the values in a number of previous posts on the Book of...
By Arun Sirpal
When the evidence names the database, it says so. When it doesn’t, it stops....
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers