Script to get a list of publications an article is in
Script to get a list of publications an article is in
2010-12-17 (first published: 2010-12-08)
3,743 reads
Script to get a list of publications an article is in
2010-12-17 (first published: 2010-12-08)
3,743 reads
This script reveals the state of your indexes. It breaks down the indexes where they are partitioned, matching the index to it’s partition and filegroup.
2010-12-16 (first published: 2010-04-22)
7,536 reads
This function evaluates the statement like '4+5*6-3' and returns the numeric value.It is just like Eval funcction in javascript.
2010-12-15 (first published: 2010-12-08)
1,046 reads
2010-12-14 (first published: 2010-11-30)
3,839 reads
Script to grant exec permission to all sps in a db
2010-12-13 (first published: 2010-12-09)
1,720 reads
know all database columns names and data types and lenght with the minimum effort
2010-12-09 (first published: 2010-12-06)
3,024 reads
A script to reveal which logins have access to your sql server via windows groups.
2010-12-09 (first published: 2010-08-26)
2,416 reads
2010-12-08 (first published: 2010-12-03)
1,976 reads
2010-12-07 (first published: 2010-11-30)
2,181 reads
2010-12-06 (first published: 2010-11-22)
2,603 reads
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
SELECT * feels convenient, but in SQL Server it bloats I/O, burns network bandwidth,...
I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers