2010-12-03 (first published: 2010-11-22)
1,697 reads
2010-12-03 (first published: 2010-11-22)
1,697 reads
A useful script that I wrote that will sample the DMV sys.dm_os_performance_counters table to provide an average PLE captured in (1) minute intervals.
2010-12-01 (first published: 2010-11-16)
1,668 reads
SQL Function to Split Comma Separated Values and Insert into Table
2010-11-30 (first published: 2010-11-07)
4,207 reads
2010-11-26 (first published: 2010-11-04)
579 reads
2010-11-18 (first published: 2009-07-20)
2,938 reads
Stored procedure to provide clean output of system name and uptime since last restart
2010-11-16 (first published: 2010-11-08)
1,249 reads
Script will display current status of SQL server services and even show if not installed. Works on SQL 2005,2008 2008R2. Both 32 and 64 bit servers.
2010-11-15 (first published: 2010-11-09)
3,527 reads
In the last script, we covered removing the trailing partition in a Range Right, date valued partition. This script adds a new (empty) partition to the partition scheme.
2010-11-12 (first published: 2009-12-17)
1,062 reads
This is simple script to change string to title case. It will take string in any case and convert it to initcap.
2010-11-12 (first published: 2010-10-19)
1,519 reads
This script automatically splits a partitioned table, merges the partition function and then drops the associated file group for the partition.
2010-11-11 (first published: 2009-12-17)
2,188 reads
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
SELECT * feels convenient, but in SQL Server it bloats I/O, burns network bandwidth,...
I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers