2011-04-27 (first published: 2011-04-21)
2,742 reads
2011-04-27 (first published: 2011-04-21)
2,742 reads
2011-04-26 (first published: 2011-04-20)
2,667 reads
Execute this script to get information on SQL server, databases, processes, memory, buffer, locks, etc.
2011-04-21 (first published: 2009-09-03)
5,643 reads
Monitoring space in production server is one of the top priority tasks for a DBA. This script will automate it
2011-04-19 (first published: 2009-05-28)
6,104 reads
This script will reindex (online) any index eligible to be reindexed online. Accepts a day of week parameter for full offline reindexing.
2011-04-18 (first published: 2008-10-01)
4,692 reads
Uses sp_MsForEachDb, locates members in db_datareader with permissions other than Select and Connect.
2011-04-14 (first published: 2011-03-29)
1,092 reads
Retrieve the charindex of matching string for the desired occurrence
2011-04-13 (first published: 2011-04-06)
1,502 reads
converting a date from existing timezone to some different time zone covering multiple location
2011-04-05 (first published: 2011-03-24)
1,186 reads
2011-04-01 (first published: 2008-02-23)
3,797 reads
Third in a series of scripts demonstrating a quantitative comparison between the text of two stored procedures
2011-03-30 (first published: 2009-02-16)
2,441 reads
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
By ChrisJenkins
Have you been thinking about migrating your reporting to Microsoft Fabric or Snowflake but...
The Joyful Craftsmen has become the new owner of Revolt BI. The merger creates...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
Comments posted to this topic are about the item SQL Server Enum Implementation: A...
Comments posted to this topic are about the item BIT_COUNT I
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers