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Client data received for processing may have invalid records based on processing requirements. Identifying and dealing with bad records in a specific scenario is the object of this article.
This editorial was originally published on Jan 17, 2007. It is being republished as Steve is on vacation. This one deals with data security.
There are a number of ways of measuring and identifying I/O-related performance information for your SQL Server database instances.
Ben Kubicek wrote a recursive function that solves simple math expressions in a select statement. Read about this creative use of T-SQL.
This editorial was originally published on Feb 5, 2007 and is being re-run as Steve is on vacation. Is this the advice you'd give, or take, in a DR situation? Steve thinks it's not.
This week saw the release of RC2 of SQL Server 2012 and marks an important milestone towards the next release of SQL Server.
SQL Server has produced some excellent High Availability options, but I was looking for an option that would allow me to access my secondary database without it being read-only or in restoring mode. I need the ability to see transactions occur and query the secondary database.
Red Gate survey asks would you take cash or trip of a lifetime?
A RAG pipeline that answers questions in the demo is not the same thing...
By Steve Jones
“A multitude of bad ideas is necessary for one good idea” – from Excellent...
Yesterday I gave a talk for MSSQLTips called “Building a DBA Agent for Your...
ALAMAT : Jl. Raya Tumpang No.1, Ledoksari, Tumpang, Kec. Tumpang, Kabupaten Malang, Jawa Timur...
Comments posted to this topic are about the item Adding new column with DEFAULT
I've got a web application for my side business. I've added a SQL Server...
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers