2012-02-28 (first published: 2010-10-20)
9,590 reads
2012-02-28 (first published: 2010-10-20)
9,590 reads
2012-02-23 (first published: 2010-10-13)
11,944 reads
2012-02-21 (first published: 2010-10-06)
9,420 reads
2012-02-16 (first published: 2010-09-29)
8,641 reads
2013-05-17 (first published: 2010-09-22)
11,229 reads
2012-02-09 (first published: 2010-09-15)
10,172 reads
2012-02-07 (first published: 2010-09-08)
9,735 reads
2012-02-02 (first published: 2010-09-01)
9,294 reads
2012-01-31 (first published: 2010-08-11)
9,231 reads
2012-01-26 (first published: 2010-08-04)
9,103 reads
By Patrick
SQL Server Audit is an efficient way to track and log events that occur...
I presented at SQL Saturday Pittshburgh this past weekend about populating your data warehouse...
By Steve Jones
A customer was asking recently about the RPO for their estate, and I showed...
I am trying to access LocalDB 2012 on my Windows 7 SP1 PC. I...
Comments posted to this topic are about the item The Modern Algorithm of Chance
Comments posted to this topic are about the item Use Logic Apps To Save...
I have this data in my Customer table:
CustomerID CustomerName 1 Steve 2 Andy 3 Brian 4 Allen 5 DevinI run this code:
SELECT t.CustomerID , c.value FROM ( SELECT CustomerID , STRING_AGG (CustomerName, ',') AS me FROM customer GROUP BY CustomerID) t CROSS APPLY STRING_SPLIT(me, ',') c;What is returned? See possible answers