Viewing 15 posts - 13,351 through 13,365 (of 13,876 total)
Wow, comprehensive answer! So there is a God and he understands SQL Server ... all is well ![]()
September 15, 2005 at 3:28 am
What message are you getting?
September 14, 2005 at 5:22 am
Not in SQL Server - but perhaps it's something to do with Magic Software ???, check out:
September 14, 2005 at 5:20 am
This appears to be a logon error - possibly because the external app is trying to log in as sa and the sa password has been changed on the server. ...
September 14, 2005 at 2:38 am
This gets you some of the way and may give you an idea about how to finish it off:
select b1.*, sum(b2.units) CumUnits
from basetable b1
join basetable b2 on b1.tdate >= b2.tdate
group...
September 13, 2005 at 8:12 am
Why not recast this as a conditional insert?
if not exists (SELECT destination FROM filespath WHERE Destination = @a)
begin
INSERT INTO FilesPath (Path,Destination)
VALUES (@a,@b)
end
September 13, 2005 at 3:57 am
Hi Bob
Can you break the script into several stored procedures and then bring these all together in a master stored procedure? Just use
exec [procname]
within a stored proc to execute another...
September 13, 2005 at 2:36 am
I reckon people would be more keen to help if you posted a copy of pornstar.mdb ![]()
Under what circumstances does the error message appear?...
September 6, 2005 at 3:19 pm
Watch out for the possibility that INSERT statements can add a row that has its clustered index value 'between' existing entries - possibly forcing a major rewrite of data on...
September 6, 2005 at 3:13 pm
Hi Ray, just a quick comment on your response - your final query will, in fact, only return those orders that are placed at the same millisecond as the query...
September 5, 2005 at 4:13 pm
I would have thought that the GROUP BY clause would ensure that city5 would not be displayed 3 times - ** please test and post the results along with the...
September 5, 2005 at 6:12 am
I'm having a bit of trouble working out what you want. Is it something like this?
select t1.city, t1.name, sum(no_of_games)
from test1 t1
join test2 t2 on t1.city = t2.city
join test3...
September 5, 2005 at 4:21 am
By "reflexive", do you mean a self-join? If so, I agree with Phill Cart's response - just add the table again and Access will create an alias for it.
August 29, 2005 at 9:23 am
There is - use the SQL pane and write the query yourself. Is that what you mean?
August 29, 2005 at 3:07 am
It is possible to restore without the log file - SQL Server should create a new log for you. Are you working in EM or QA and exactly what is...
August 28, 2005 at 3:10 am
Viewing 15 posts - 13,351 through 13,365 (of 13,876 total)