Git, GitHub and Visual Studio Code for SQL Server
Learn how to get started with Git and Visual Studio Code.
2024-08-05
5,763 reads
Learn how to get started with Git and Visual Studio Code.
2024-08-05
5,763 reads
Learn how you can create and use a Jupyter Notebook in VS Code.
2024-07-22
4,234 reads
Learn how you can connect ChatGPT to VS Code and use it to help you fix your code.
2023-04-10
68,118 reads
Learn how to get started with Git and avoid the command line by using VS Code or Azure Data Studio.
2022-05-11
4,937 reads
2021-02-19
263 reads
Visual Studio Code is rapidly gaining in popularity, but is it all it could be, or is there room for improvement? Redgate is embarking on some research to better understand how you are using this lightweight editor, and where it can be improved. Have your say by filling in this short survey!
2017-05-19 (first published: 2017-05-17)
5,394 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
hi, i noticed the sqlhealth extended event is on by default , and it...
Using New-AzSqlInstanceServerTrustCertificate to import a certificate and get the message New-AzSqlInstanceServerTrustCertificate: Long running operation...
Comments posted to this topic are about the item Refactoring SQL Code, which is...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers